以下的文章主要向大家描述的是SQL server合并分拆表的实际操组方法的描述,本文是以SQL server合并分拆表的实际操作的应用代码的方式来引出其实际操作步骤,以下就是文章的主要内容描述 。
合并分拆表
(Roy)生成測試數據
- if not object_id(Tab) is null
- drop table Tab
- Go
- Create table Tab([Col1] int,[Col2] nvarchar(1))
- Insert Tab
- select 1,Na union all
- select 1,Nb union all
- select 1,Nc union all
- select 2,Nd union all
- select 2,Ne union all
- select 3,Nf
- Go
合并表:
SQL2000用函数:
- go
- if object_id(F_Str) is not null
- drop function F_Str
- go
- create function F_Str(@Col1 int)
- returns nvarchar(100)
- as
- begin
- declare @S nvarchar(100)
- select @S=isnull(@S+,,)+Col2 from Tab where Col1=@Col1
- return @S
- end
- go
- Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab
- go
SQL2005用XML:
方法1:
- select
- a.Col1,Col2=stuff(b.Col2.value(/R[1],nvarchar(max)),1,1,)
- from
- (select distinct COl1 from Tab) a
- Cross apply
- (select COl2=(select N,+Col2 from Tab where Col1=a.COl1 For XML PATH(), ROOT(R), TYPE))b
方法2:
- select
- a.Col1,COl2=replace(b.Col2.value(/Tab[1],nvarchar(max)),char(44)+char(32),char(44))
- from
- (select distinct COl1 from Tab) a
- cross apply
- (select Col2=(select COl2 from Tab where COl1=a.COl1 FOR XML AUTO, TYPE)
- .query(<Tab>
- {for $i in /Tab[position()<last()]/@COl2 return concat(string($i),",")}
- {concat("",string(/Tab[last()]/@COl2))}
- Tab>)
- )b
- SQL05用CTE:
- ;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab)
- ,Roy2 as
- (select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1
- union all
- select a.Col1,cast(b.COl2+,+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1)
- select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0)
生成结果:
- /*
- Col1 COl2
- ----------- ------------
- 1 a,b,c
- 2 d,e
- 3 f
- (3 行受影响)
- */
-
以上的相关内容就是对SQL server合并分拆表的方法的介绍,望你能有所收获 。