PHP直接修改表内容DataGrid功能实现代码 |
由于需要连接Oracle所以从二次开发和页面样式来说个人觉得phpMyDataGrid还是比较好上手 。 create database `guru`; USE `guru`; CREATE TABLE `employees` ( `id` int(6) NOT NULL auto_increment, `name` char(20) default NULL, `lastname` char(20) default NULL, `salary` float default NULL, `age` int(2) default NULL, `afiliation` date default NULL, `status` int(1) default NULL, `active` tinyint(1) default NULL, `workeddays` int(2) default NULL, `photo` char(30) default NULL, PRIMARY KEY (`id`) ) insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (1, Ana, Trujillo,2000,45, 2005-05-13,1,1,10, 1.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (2, Jennifer, Aniston,3500,23, 2004-10-22,1,0,0, 2.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (3, Michael, Norman,1200,19, 2007-01-10,1,1,5, 3.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (4, Vanessa, Black,6500,31, 2000-11-05,1,1,30, 4.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (5, Michael, Strauss,3200,45, 2006-10-21,2,0,22, 5.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (6, William, Brown,2300,21, 2001-03-10,3,1,10, 6.jpg); insert into `employees` (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`) values (7, Lucca, Normany,2800,36, 2006-10-02,3,1,20, 7.jpg); 2. PHP程序介绍 phpMyDataGrid主要是通过phpmydatagrid.class.php,dgscripts.js来实现的,总共加起来不到100kB,又是一个小巧的软件 。对于这两个文件就不多讲了,感兴趣的同学可以“打包带走”回去慢慢品 。主要介绍该软件的使用方法,即实例 datagrid_for_mysql.php 。先看一下页面示意图: 程序讲解: <?php include ("phpmydatagrid.class.php"); $objGrid = new datagrid; $objGrid->closeTags(true); $objGrid->friendlyHTML(); $objGrid->methodForm("get"); //连接数据库 $objGrid->conectadb("127.0.0.1", "root", "root", "guru");//加密字符串 $objGrid->salt("Myc0defor5tr0ng3r-Pro3EctiOn"); $objGrid->language("en"); //最后一列显示的功能键,从左向右功能为“新增键”、“编辑键”、“删除键”、“浏览键” 。 $objGrid->buttons(true,true,true,true); //修改数值时产生的Form名称 $objGrid->form(employee, true); //可检索列名 $objGrid->searchby("name,lastname"); //需要读取的表 $objGrid->tabla("employees"); //索引值用于修改数据 $objGrid->keyfield("id"); //分页显示行数 $objGrid->datarows(20); //默认排序方式 $objGrid->orderby("name", "ASC"); //显示列设置,相关设置可参考phpmydatagrid.class.php $objGrid->FormatColumn("id", "ID Employee", 5, 5, 1, "50", "center", "integer"); $objGrid->FormatColumn("name", "Name", 30, 30, 0, "150", "left"); $objGrid->FormatColumn("lastname", "Last name", 30, 30, 0, "150", "left"); $objGrid->FormatColumn("age", "Age", 5, 5, 0, "50", "right");//自定义日期格式 $objGrid->FormatColumn("afiliation", "Afiliation Date", 10, 10, 0, "100", "center", "date:dmy:/");//编辑时可以自定义为<Select>模式 $objGrid->FormatColumn("status", "Status", 5, 5, 0, "60", "left", "select:1_Single:2_Married:3_Divorced"); //编辑时可以自定义为<CheckBox>模式 $objGrid->FormatColumn("active", "Active", 2, 2, 0,"50", "center", "check:No:Yes");//自定义货币显示形式 $objGrid->FormatColumn("salary", "Salary", 10, 10, 0, "90", "right", "money:€");//将数据以柱状图显示 $objGrid->FormatColumn("workeddays", "Work days", 5, 2, 0, "50", "right", "chart:percent:val:31"); $objGrid->checkable(); $objGrid->setHeader(); $objGrid->ajax(silent); echo <html> <head><title>PHPDataGrid</title></head> <body><div align="center"><br />; //生成DataGrid $objGrid->grid(); echo </div></body></html>;//关闭数据库连接 $objGrid->desconectar(); ?> 3. 基于Oracle简介 对于Oracle的读取主要是把phpmydatagrid.class.php中与MySQL连接的函数修改为Oracle,本篇是通过sqlrelay进行的Oracle连接,当然也可以使用PHP自带的OCI8模块(效率有些低),修改后另存为phporadatagrid.class.php即可在其他程序(datagrid_for_oracle.php)中调用 。 以上就是教大家PHP如何直接修改表内容DataGrid功能的全过程,还有对数据库的了解,希望本文对大家的学习有所帮助 。 |