PHP获取一年有几周以及每周开始日期和结束日期 |
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本文标签：php计算日期,php计算日期差 最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期 。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期 代码一：
<?php
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year = (int)$_GET[year];
$week = (int)$_GET[week];
$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
echo $year . 年一共有 . $weeks . 周<br />;
if ($week > $weeks || $week <= 0)
{
$week = 1;
}
if ($week < 10)
{
$week = 0 . $week;
}
$timestamp[start] = strtotime($year . W . $week);
$timestamp[end] = strtotime(+1 week -1 day, $timestamp[start]);
echo $year . 年第 . $week . 周开始时间戳： . $timestamp[start] . <br />;
echo $year . 年第 . $week . 周结束时间戳： . $timestamp[end] . <br />;
echo $year . 年第 . $week . 周开始日期： . date("Y-m-d", $timestamp[start]) . <br />;
echo $year . 年第 . $week . 周结束日期： . date("Y-m-d", $timestamp[end]);
?>
代码二：
<?php
header("Content-type:text/html;charset=utf-8");
function getIsoWeeksInYear($year)
{
$date = new DateTime;
$date->setISODate($year, 53);
return ($date->format("W") === "53" ? 53 : 52);
}
function weekday($custom_date)
{
$week_start = date(d-m-Y, strtotime(this week monday, $custom_date));
$week_end = date(d-m-Y, strtotime(this week sunday, $custom_date));
$week_array[0] = $week_start;
$week_array[1] = $week_end;
return $week_array;
}
echo <br> Weeks in 2013<br> . getIsoWeeksInYear(2013);
$weekday = weekday(strtotime(date(d-m-Y, strtotime(5-8-2013))));
echo <br> 10-8-2013;
echo <br>Start: . $weekday[0];
echo <br>End: . $weekday[1];
?>
以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助 。 |
