Thinkphp+smarty+uploadify实现无刷新上传


本文实例讲述了Thinkphp+smarty+uploadify实现无刷新上传的方法 。分享给大家供大家参考 。具体如下:

模板文件代码:

<!DOCTYPE html>
<html lang="cn">
 <head>
  <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
  <link href="<{$smarty.const.PUBLIC_PATH}>/Uploadify/uploadify.css" rel="stylesheet" type="text/css" />
  <script src="<{$smarty.const.PUBLIC_PATH}>/Uploadify/jquery.js" type="text/javascript"></script>
  <script src="<{$smarty.const.PUBLIC_PATH}>/Uploadify/jquery.uploadify.min.js" type="text/javascript"></script>
 </head>
 <script type="text/javascript">
  $(function() {
   $("#file_upload").uploadify({
    //指定swf文件
    swf: <{$smarty.const.PUBLIC_PATH}>/Uploadify/uploadify.swf,
    //后台处理的页面
    uploader: "<{U(home/Login/Uploads,,false)}>",
    //按钮显示的文字
    buttonText: 上传图片,
     //显示的高度和宽度
    "height" : 30,
    fileTypeDesc: Image Files,
    //允许上传的文件后缀
    fileTypeExts: *.gif; *.jpg; *.png,
    //发送给后台的其他参数通过formData指定
    //formData: { someKey: someValue, someOtherKey: 1 },
    "method" : post,//方法,服务端可以用$_POST数组获取数据
    removeTimeout  : 1,
    "onUploadSuccess" : uploadPicture
  });
  //可以根据自己的要求来做相应处理
  function uploadPicture(file, data){
    var data = eval(( + data + ));
   if(data.errorcode){
    alert(data.errormsg); 
   } else {
    alert(data.errormsg);
   }
  } 
 });
</script>
 <body>
  <input type="file" name="file_upload" id="file_upload" />
 </body>
</html>

控制器代码:

public function uploads(){
  $arr = array( "errorcode"=>"1","errormsg"=>"上传成功!");
  $model = M(applicant);
  if (!empty($_FILES)) {
    //图片上传设置
    $config = array( 
    maxSize => 1000000, 
    rootPath => Public,
    savePath => /Uploads/, 
    saveName => array(uniqid,), 
    exts  => array(jpg, gif, png, jpeg), 
    autoSub => false, 
    subName => array(date,Ymd),
   );
   $upload = new \Think\Upload($config);// 实例化上传类
  $info = $upload->upload();
   if($info){
    $arr[errorcode] = "0";
   } else {
    $arr["errorcode"] = "1";
    $arr["errormsg"] = $upload->getError();
   }
   /* 返回JSON数据 */
   $this->ajaxReturn($arr);
  }
}

希望本文所述对大家的php程序设计有所帮助 。