Oracle中scott表结构与简单查询实例分析 |
本文实例讲述了Oracle中scott表结构与简单查询的方法 。分享给大家供大家参考 。具体分析如下: 1、scott用户的表的结构 查看表结构 desc 表名;//desc emp; dept表: salgrade表: bonus表: 2、简单查询 1.查询不重复的职位 select distinct job from emp; 2.查询年薪,起别名,别名不要用单引号括起来 select sal*12 [as] income from emp; 3.简单查询中可以使用"||"连接查询的字段 select empno ||,|| ename from emp; sql语句中的字符串用单引号表示 4.在oracle中数据时区分大小写的 select * from emp where job =CLERK; 查询不是办事员的雇员信息 select * from emp where job!=CLERK; select * from emp where job<>CLERK; select * from emp where NOT job=CLERK; 5.BETWEEN ……AND 大于等于 小于等于 select * from emp where sal between 1500 and 3000; 也可以求反 select * from emp where sal not between 1500 and 3000; 也可以是日期 select * from emp where hiredate between 01-1月 -1981 and 31-12月 -81; 6. 判断是否为空IS(NOT)NULL select * from emp where comm Is not null; select * from emp where not comm Is null; 7.IN操作符 select * from emp where empno in (7521,7844,5555); select * from emp where empno not in (7521,7844,5555); 关于NOT IN select * from emp where empno in (7521,7844,null); 如果现在使用的是NOT IN操作符,如果查询范围之中有了null,则不会有任何的结果返回 select * from emp where not empno in (7521,7844,null); select * from emp where empno not in (7521,7844,null); 8.LIKE子句 匹配符号: select * from emp where ename like A%; 查询第二个字母为"A"的雇员 select * from emp where ename like _A%; 查询含有字母为"A"的雇员 select * from emp where ename like %A%; 查询不含有字母为"A"的雇员 select * from emp where not ename like %A%; select * from emp where ename not like %A%; LIKE %% 表示查询全部数据 select * from emp where empno like %% 9.数据的排序 order by 字段 [ASC|DESC][,字段 [ASC|DESC]……]; order by子句必须在where子句之后,在所有sql语句最后 select * from emp order by sal desc; 先按工资排序,再按照雇佣日期排序 select * from emp order by sal desc,hiredate; 希望本文所述对大家的Oracle程序设计有所帮助 。 |