使用SQLyog的sql条件查询方式 |
1. 等值判断(=)#查询符合条件的数据 SELECT employee_id,first_name,salary FROM t_employees WHERE salary = 10000; 2. 不等值判断(>、<、>=、 <= 、!= 、<>)和逻辑判断(and、or、not)!=和<>都是不等于 # 查询员工的工资再10000'40000之间的员工信息(编号,名字,薪资) SELECT employee_id,first_name,salary FROM t_employees WHERE salary >= 10000 AND salary <=40000; 3.区间判断(between and)#查询员工的薪资在10000'50000之间的员工信息(编号,名字,薪资) SELECT employee_id,first_name,salary FROM t_employees WHERE salary BETWEEN 10000 AND 50000; 4. NULL值判断(IS NULL、IS NOT NULL)#查询没有提成的员工信息(编号,名字,薪资,提成) SELECT employee_id,first_name,salary,commission_pct FROM t_employees WHERE commission_pct IS NULL; 5. 枚举查询#查询部门编号为90、30的员工信息(编号,名字,薪资,部门编号) SELECT employee_id,first_name,salary,department_id FROM t_employees WHERE department_id IN(90,30); 6. 模糊查询LIKE_ (单个任意字符) 列名 LIKE ‘张_' LIKE % (任意长度的任意字符) 列名 LIKE ‘张%' #查询名字已“L”开头的员工信息(编号,名字,薪资,部门编号) SELECT employee_id,first_name,salary,department_id FROM t_employees WHERE first_name LIKE 'L%'; #查询名字已“L”开头并且长度为3的员工信息(编号,名字,薪资,部门编号) SELECT employee_id,first_name,salary,department_id FROM t_employees WHERE first_name LIKE 'L__'; 7.分支结构查询CASE WHEN 条件1 THEN 结果1 WHEN 条件2 THEN 结果2 WHEN 条件3 THEN 结果3 ELSE 结果4 END #查询员工信息(编号,名字,薪资,薪资级别<对应条件表达式生成>) SELECT employee_id,first_name,salary, CASE WHEN salary>40000 THEN 'A' WHEN salary>30000 AND salary <40000 THEN 'B' WHEN salary>20000 AND salary <30000 THEN 'C' WHEN salary>10000 AND salary <20000 THEN 'D' ELSE 'E' END AS '薪资级别' FROM t_employees; 总结以上为个人经验,希望能给大家一个参考,也希望大家多多支持 。 |