js跳转页面方法实现汇总 |
本文标签:跳转页面,自动跳转 复制代码 代码如下: <span id="tiao">3</span><a href="javascript:countDown"></a>布丁足迹;秒后自动跳转……<meta http-equiv=refresh content=3;url=/search/billsearch.jsp</ul> <!--脚本开始--> <script language="javascript" type=""> function countDown(secs){ tiao.innerText=secs; if(--secs>0) setTimeout("countDown("+secs+")",1000); } countDown(3); </script> <!--脚本结束--> 按钮式: <INPUT name="pclog" type="button" value="GO" onClick="location.href=http://www.ddhbb.com/"> 链接式: <a href="javascript:history.go(-1)">返回上一步</a> <a href="<%=Request.ServerVariables("HTTP_REFERER")%>">返回上一步</a> 直接跳转式: <script>window.location.href=http://www.ddhbb.com;</script> 开新窗口: <a href="javascript:" onClick="window.open(http://www.ddhbb.com/blog/guestbook.asp,,height=500,width=611,scrollbars=yes,status=yes)">布丁足迹</a> JS跳转页面参考代码 第一种: <script language="javascript" type="text/javascript"> window.location.href="login.jsp?backurl="+window.location.href; </script> 第二种: <script language="javascript"> alert("返回"); window.history.back(-1); </script> 第三种: <script language="javascript"> window.navigate("top.jsp"); </script> 第四种: <script language="JavaScript"> self.location=top.htm; </script> 第五种: <script language="javascript"> alert("非法访问!"); top.location=xx.jsp; </script> =====javascript中弹出选择框跳转到其他页面===== <script language="javascript"> <!-- function logout()...{ if (confirm("你确定要注销身份吗?是-选择确定,否-选择取消"))...{ window.location.href="logout.asp?act=logout" } } --> </script> =====javascript中弹出提示框跳转到其他页面===== <script language="javascript"> <!-- function logout()...{ alert("你确定要注销身份吗?"); window.location.href="logout.asp?act=logout" } --> </script> [/code] |