用shell抽取，更新db2的数据

#SQL文定义
SQL="SELECT AAA, BBB, CCC FROM MYTBL1"
#执行SQL
SDATA=`db2 "$SQL"`
#返回值判断
if [ $? -ne 0 ]
then
#显示db2返回的错误信息
echo "$SDATA"
exit 1
fi
#对取得的数据进行处理  。
echo "$SDATA" | sed -e 4,/^$/!d;/^$/d |
while read AAA BBB CCC
do
  echo "AAA IS $AAA, BBB IS $BBB, CCC IS $CCC"
done
#取得数据件数
echo "$SDATA" | sed -n -e /^$/{1,3d;n;s/[^0-9]*\([0-9]*\)[^0-9]*/\1/;p;} | read CNT
echo "The count of selected data is $CNT."
exit 0

SQL="UPDATE MYTBL1 SET AAA=2005,BBB=05,CCC=12"
#执行SQL
SDATA=`db2 -a "$SQL"`
#取得SQLCODE
echo "$SDATA" | sed -n -e s/^.*sqlcode: \([-,0-9][0-9]*\).*/\1/p | read SQLCODE
echo "Sqlcode is $SQLCODE."
#取得SQLSTATE
echo "$SDATA" | sed -n -e s/^.*sqlstate: \([-,0-9][0-9]*\).*/\1/p | read SQLSTATE
echo "Sqlstate is $SQLSTATE."
#取得更新件数(即sqlerrd的第三个值)
echo "$SDATA" | sed -n -e /sqlerrd/s/^.*(3) \([-,0-9][0-9]*\).*/\1/p | read UPDCNT
echo "Updated datas count is $UPDCNT."
#取得sqlerrd的第五个值
echo "$SDATA" | sed -n -e /sqlerrd/{n;s/^.*(5) \([-,0-9][0-9]*\).*/\1/;p;} | read SQLERRD5
echo "Sqlerrd(5) is $SQLERRD5."