asp.net Menu控件+SQLServer实现动态多级菜单 |
本文标签:Menu控件,多级菜单 首先是数据表的设计
复制代码 代码如下: using System; using System.Data; using System.Configuration; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; using System.Data.SqlClient; using System.Data.ProviderBase; public partial class _Default : System.Web.UI.Page { public int treeID; protected void Page_Load(object sender, EventArgs e) { SqlConnection CN = new SqlConnection("server=.;Trusted_Connection=SSPI;database=MENUDB"); //MENUDB是数据库名 //设定数据库操作命令 CN.Open(); SqlCommand Scmd = new SqlCommand("select * from TB_MENU where treeId=0 order by position", CN); //选出根菜单 SqlDataReader odr = Scmd.ExecuteReader(); while (odr.Read()) //循环读取 { MenuItem menuNode = new MenuItem(); menuNode.Text = odr["names"].ToString(); menuNode.Value = odr["id"].ToString(); menuNode.Enabled = true; menuNode.NavigateUrl = odr["page"].ToString(); Menu1.Items.Add(menuNode); //添加到根菜单 treeID = Convert.ToInt16(odr["id"].ToString()); addchildmenu(menuNode); } //关闭数据库连接 Scmd.Connection.Close(); } protected void addchildmenu(MenuItem pnode) //添加子菜单 { SqlConnection CN = new SqlConnection("server=.;Trusted_Connection=SSPI;database=MENUDB"); ? //设定数据库操作命令 CN.Open(); SqlCommand Scmd1 = new SqlCommand("select * from TB_MENU where treeID=" + treeID + "", CN); ? SqlDataReader odr = Scmd1.ExecuteReader(); while (odr.Read()) { MenuItem menuNode = new MenuItem(); menuNode.Text = odr["names"].ToString(); menuNode.Value = odr["id"].ToString(); menuNode.Enabled = true; menuNode.NavigateUrl = odr["page"].ToString(); pnode.ChildItems.Add(menuNode); //为当前菜单项添加子菜单 treeID = Convert.ToInt16(odr["id"].ToString()); addchildmenu(menuNode); //循环添加子菜单 } //关闭数据库连接 Scmd1.Connection.Close(); } } 最终效果如下图 |